A) Toughness
B) Proof Resilience
C) Ductility
D) Malleability

According to IS 800:2007, Clause 2, Proof resilience is defined as the maximum strain energy that a material can absorb per unit volume without any permanent deformation. This is an important design consideration as it indicates the ability of a material/component to absorb shock and impact loads by undergoing elastic deformation. Table 2 of IS 800:2007 provides the resilience values for structural steel.

The correct option is B) Resilience

See also  A rectangular concrete beam has a width of 300 mm and a depth of 500 mm. It is subjected to a shear force of 20 kN. What is the shear stress at a depth of 150 mm from the neutral axis?

Subscribe to FREE Weekly Civil Engg. Newsletter

Once in a week we will send important updates and latest news in the civil engineering world.

All data is private and secure. We store data on Mailchimp to send newsletter campaigns.

N Lavanya

Lavanya is a passionate content writer about Structural Design, Grouting, Columns, Beams etc. She has 5 years of experience in teaching in Civil Engg. She enjoys writing complete guides and tips. Her passion is in building materials, construction standards, foundation design and building codes.

Similar Posts

If a part is constrained to move and heated, it will develop:

A) Tensile stressB) Compressive stressC) Shear stressD) No stress Table of Contents Explanation: Explanation: As per theory of thermal stresses, when a body is restricted from free expansion or contraction, it develops internal stresses when subjected to change in temperature. If a constrained part is heated, it tends to expand. But restriction to movement causes…

The internal diameter of a cast iron pipe is 300 mm and its thickness is 10 mm. If the pipe is supported at two points 8 m apart, what is the internal cross-sectional area of the pipe as per IS:1239 (Part 1)?

A) 0.0707 m2B) 0.0616 m2C) 0.0524 m2D) 0.0491 m2 As per IS 1239 (Part 1)-2004 for Pipes, the internal diameter is 300 mm or 0.3 m. The internal radius r = (Internal diameter/2) = 0.3/2 = 0.15 m The internal cross-sectional area A = πr2= π x (0.15)2= 0.0707 m2 Therefore, option A is the…

A round bar specimen is subjected to a tensile test. After fracture, it is observed that the diameter at the fractured section remains approximately the same as the original diameter. What material was the round bar most likely made of?

A) Mild steelB) Cast ironC) AluminumD) Copper Explanation: As per IS 1608, when a ductile material like mild steel is subjected to tensile test, it undergoes significant plastic deformation before failure. This causes necking at the fractured section, where the diameter reduces substantially. However, brittle materials like cast iron and aluminum do not undergo plastic…

Leave a Reply

Your email address will not be published. Required fields are marked *