A) 0.0707 m2
B) 0.0616 m2
C) 0.0524 m2
D) 0.0491 m2

As per IS 1239 (Part 1)-2004 for Pipes, the internal diameter is 300 mm or 0.3 m.

The internal radius r = (Internal diameter/2) = 0.3/2 = 0.15 m

The internal cross-sectional area A = πr2
= π x (0.15)2
= 0.0707 m2

Therefore, option A is the correct answer.

See also  If a part is constrained to move and heated, it will develop:

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N Lavanya

Lavanya is a passionate content writer about Structural Design, Grouting, Columns, Beams etc. She has 5 years of experience in teaching in Civil Engg. She enjoys writing complete guides and tips. Her passion is in building materials, construction standards, foundation design and building codes.

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